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4402161376681 = 7162002272911
BaseRepresentation
bin100000000001111010101…
…0000111101110110101001
3120120211202012021101100011
41000003311100331312221
51034111111303023211
613210154112011521
7633021443210635
oct100036520756651
916524665241304
104402161376681
111447a45373292
125b1202b30ba1
1325c178164393
141130cc5a7dc5
157979c4e1921
hex400f543dda9

4402161376681 has 4 divisors (see below), whose sum is σ = 4464163649664. Its totient is φ = 4340159103700.

The previous prime is 4402161376673. The next prime is 4402161376687. The reversal of 4402161376681 is 1866731612044.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4402161376681 - 23 = 4402161376673 is a prime.

It is a super-2 number, since 2×44021613766812 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4402161376687) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31001136385 + ... + 31001136526.

It is an arithmetic number, because the mean of its divisors is an integer number (1116040912416).

Almost surely, 24402161376681 is an apocalyptic number.

It is an amenable number.

4402161376681 is a deficient number, since it is larger than the sum of its proper divisors (62002272983).

4402161376681 is an equidigital number, since it uses as much as digits as its factorization.

4402161376681 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62002272982.

The product of its (nonzero) digits is 1161216, while the sum is 49.

The spelling of 4402161376681 in words is "four trillion, four hundred two billion, one hundred sixty-one million, three hundred seventy-six thousand, six hundred eighty-one".

Divisors: 1 71 62002272911 4402161376681