Base | Representation |
---|---|
bin | 10100000001001101011001… |
… | …11011001001001100001001 |
3 | 12202212110112100000112001001 |
4 | 22000212230323021030021 |
5 | 21232224044334030433 |
6 | 233343234240455001 |
7 | 12162325501346626 |
oct | 1200465473111411 |
9 | 182773470015031 |
10 | 44022021001993 |
11 | 130326a8227441 |
12 | 4b2b91991a461 |
13 | 1b74349689698 |
14 | ac296a2a534d |
15 | 5151a90a357d |
hex | 2809acec9309 |
44022021001993 has 4 divisors (see below), whose sum is σ = 44022706906320. Its totient is φ = 44021335097668.
The previous prime is 44022021001963. The next prime is 44022021002039. The reversal of 44022021001993 is 39910012022044.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 44022021001993 - 213 = 44022020993801 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (44022021001963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342855883 + ... + 342984256.
It is an arithmetic number, because the mean of its divisors is an integer number (11005676726580).
Almost surely, 244022021001993 is an apocalyptic number.
It is an amenable number.
44022021001993 is a deficient number, since it is larger than the sum of its proper divisors (685904327).
44022021001993 is an equidigital number, since it uses as much as digits as its factorization.
44022021001993 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 685904326.
The product of its (nonzero) digits is 31104, while the sum is 37.
The spelling of 44022021001993 in words is "forty-four trillion, twenty-two billion, twenty-one million, one thousand, nine hundred ninety-three".
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