Base | Representation |
---|---|
bin | 100000001000101101110… |
… | …0101000010011001110001 |
3 | 120122020102210110100201012 |
4 | 1000101123211002121301 |
5 | 1034331012240103423 |
6 | 13221011031320305 |
7 | 634046333332124 |
oct | 100213345023161 |
9 | 16566383410635 |
10 | 4416762816113 |
11 | 14531585128aa |
12 | 5b3bb8b20095 |
13 | 26066425407b |
14 | 113ab58c03bb |
15 | 79d54329078 |
hex | 4045b942671 |
4416762816113 has 4 divisors (see below), whose sum is σ = 4428416544240. Its totient is φ = 4405109087988.
The previous prime is 4416762816107. The next prime is 4416762816121. The reversal of 4416762816113 is 3116182676144.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4416762816113 - 240 = 3317251188337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4416762816163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5826863495 + ... + 5826864252.
It is an arithmetic number, because the mean of its divisors is an integer number (1107104136060).
Almost surely, 24416762816113 is an apocalyptic number.
It is an amenable number.
4416762816113 is a deficient number, since it is larger than the sum of its proper divisors (11653728127).
4416762816113 is a wasteful number, since it uses less digits than its factorization.
4416762816113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11653728126.
The product of its digits is 1161216, while the sum is 50.
The spelling of 4416762816113 in words is "four trillion, four hundred sixteen billion, seven hundred sixty-two million, eight hundred sixteen thousand, one hundred thirteen".
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