Base | Representation |
---|---|
bin | 100000001100001011100… |
… | …0000001000000111110001 |
3 | 120122221122021000102221211 |
4 | 1000120113000020013301 |
5 | 1034441231232132423 |
6 | 13224241143520121 |
7 | 634431566264230 |
oct | 100302700100761 |
9 | 16587567012854 |
10 | 4424202224113 |
11 | 14563258a9181 |
12 | 5b5534459041 |
13 | 26127b5b8839 |
14 | 1141bd93cb17 |
15 | 7a13c4dd10d |
hex | 406170081f1 |
4424202224113 has 4 divisors (see below), whose sum is σ = 5056231113280. Its totient is φ = 3792173334948.
The previous prime is 4424202224089. The next prime is 4424202224119. The reversal of 4424202224113 is 3114222024244.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4424202224113 - 29 = 4424202223601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4424202224119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316014444573 + ... + 316014444586.
It is an arithmetic number, because the mean of its divisors is an integer number (1264057778320).
Almost surely, 24424202224113 is an apocalyptic number.
It is an amenable number.
4424202224113 is a deficient number, since it is larger than the sum of its proper divisors (632028889167).
4424202224113 is an equidigital number, since it uses as much as digits as its factorization.
4424202224113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 632028889166.
The product of its (nonzero) digits is 24576, while the sum is 31.
Adding to 4424202224113 its reverse (3114222024244), we get a palindrome (7538424248357).
The spelling of 4424202224113 in words is "four trillion, four hundred twenty-four billion, two hundred two million, two hundred twenty-four thousand, one hundred thirteen".
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