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443120021345 = 56113611067489
BaseRepresentation
bin1100111001011000000…
…00101110111101100001
31120100202210111102011102
412130230000232331201
524230002211140340
6535322211524145
744004633014651
oct6345400567541
91510683442142
10443120021345
11160a20777681
1271a67bb9655
1332a2ac08981
1417638c9a361
15b7d7281215
hex672c02ef61

443120021345 has 16 divisors (see below), whose sum is σ = 540858753360. Its totient is φ = 348428083200.

The previous prime is 443120021339. The next prime is 443120021363. The reversal of 443120021345 is 543120021344.

It can be written as a sum of positive squares in 8 ways, for example, as 14189336161 + 428930685184 = 119119^2 + 654928^2 .

It is not a de Polignac number, because 443120021345 - 24 = 443120021329 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 118640 + ... + 948849.

It is an arithmetic number, because the mean of its divisors is an integer number (33803672085).

Almost surely, 2443120021345 is an apocalyptic number.

It is an amenable number.

443120021345 is a deficient number, since it is larger than the sum of its proper divisors (97738732015).

443120021345 is a wasteful number, since it uses less digits than its factorization.

443120021345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1068916.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 443120021345 its reverse (543120021344), we get a palindrome (986240042689).

Subtracting 443120021345 from its reverse (543120021344), we obtain a palindrome (99999999999).

The spelling of 443120021345 in words is "four hundred forty-three billion, one hundred twenty million, twenty-one thousand, three hundred forty-five".

Divisors: 1 5 61 305 1361 6805 83021 415105 1067489 5337445 65116829 325584145 1452852529 7264262645 88624004269 443120021345