Base | Representation |
---|---|
bin | 100000001111011100011… |
… | …0101111100101101110001 |
3 | 120200121201210221220122220 |
4 | 1000132320311330231301 |
5 | 1040100110340312431 |
6 | 13231400524551253 |
7 | 635100401130630 |
oct | 100367065745561 |
9 | 16617653856586 |
10 | 4431212432241 |
11 | 14592a2995311 |
12 | 5b69700b2529 |
13 | 261b27a56c9a |
14 | 114686995517 |
15 | 7a3ecb71b96 |
hex | 407b8d7cb71 |
4431212432241 has 16 divisors (see below), whose sum is σ = 6752353112064. Its totient is φ = 2532110362704.
The previous prime is 4431212432203. The next prime is 4431212432249. The reversal of 4431212432241 is 1422342121344.
It is not a de Polignac number, because 4431212432241 - 27 = 4431212432113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4431212432249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9206226 + ... + 9675588.
It is an arithmetic number, because the mean of its divisors is an integer number (422022069504).
Almost surely, 24431212432241 is an apocalyptic number.
It is an amenable number.
4431212432241 is a deficient number, since it is larger than the sum of its proper divisors (2321140679823).
4431212432241 is a wasteful number, since it uses less digits than its factorization.
4431212432241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 918940.
The product of its digits is 36864, while the sum is 33.
Adding to 4431212432241 its reverse (1422342121344), we get a palindrome (5853554553585).
The spelling of 4431212432241 in words is "four trillion, four hundred thirty-one billion, two hundred twelve million, four hundred thirty-two thousand, two hundred forty-one".
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