Base | Representation |
---|---|
bin | 110010011000001101000011… |
… | …0111110001000101110011001 |
3 | 2011002222221010122110220200020 |
4 | 1210300122012332020232121 |
5 | 431040230214334424423 |
6 | 4210243401111501053 |
7 | 162224113506565446 |
oct | 14460320676105631 |
9 | 2132887118426606 |
10 | 443131220233113 |
11 | 119216993461795 |
12 | 41849971087789 |
13 | 16035130276959 |
14 | 7b5d9461a09cd |
15 | 3636cd75d84e3 |
hex | 1930686f88b99 |
443131220233113 has 16 divisors (see below), whose sum is σ = 591360931805952. Its totient is φ = 295161193008000.
The previous prime is 443131220233103. The next prime is 443131220233249. The reversal of 443131220233113 is 311332022131344.
It is not a de Polignac number, because 443131220233113 - 26 = 443131220233049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (443131220233103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51636733 + ... + 59603813.
It is an arithmetic number, because the mean of its divisors is an integer number (36960058237872).
Almost surely, 2443131220233113 is an apocalyptic number.
It is an amenable number.
443131220233113 is a deficient number, since it is larger than the sum of its proper divisors (148229711572839).
443131220233113 is a wasteful number, since it uses less digits than its factorization.
443131220233113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7983376.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 443131220233113 its reverse (311332022131344), we get a palindrome (754463242364457).
The spelling of 443131220233113 in words is "four hundred forty-three trillion, one hundred thirty-one billion, two hundred twenty million, two hundred thirty-three thousand, one hundred thirteen".
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