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4431313412313 = 31477104470771
BaseRepresentation
bin100000001111011111011…
…0111001010000011011001
3120200121222211222020021120
41000132332313022003121
51040100312213143223
613231414533155453
7635103035344314
oct100367667120331
916617884866246
104431313412313
111459344996117
125b6999a8bb89
13261b429518c8
1411469615d97b
157a40696bbe3
hex407bedca0d9

4431313412313 has 4 divisors (see below), whose sum is σ = 5908417883088. Its totient is φ = 2954208941540.

The previous prime is 4431313412287. The next prime is 4431313412411. The reversal of 4431313412313 is 3132143131344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4431313412313 - 213 = 4431313404121 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4431313482313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 738552235383 + ... + 738552235388.

It is an arithmetic number, because the mean of its divisors is an integer number (1477104470772).

Almost surely, 24431313412313 is an apocalyptic number.

It is an amenable number.

4431313412313 is a deficient number, since it is larger than the sum of its proper divisors (1477104470775).

4431313412313 is a wasteful number, since it uses less digits than its factorization.

4431313412313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1477104470774.

The product of its digits is 31104, while the sum is 33.

Adding to 4431313412313 its reverse (3132143131344), we get a palindrome (7563456543657).

The spelling of 4431313412313 in words is "four trillion, four hundred thirty-one billion, three hundred thirteen million, four hundred twelve thousand, three hundred thirteen".

Divisors: 1 3 1477104470771 4431313412313