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44314624340153 = 231611191332123
BaseRepresentation
bin10100001001101110011010…
…11100010011000010111001
312210220102210100211012020122
422010313031130103002321
521302022322312341103
6234125505105503025
712222424462603436
oct1204671534230271
9183812710735218
1044314624340153
11131357aa184172
124b7857a041a75
131b95b0ac6c2bb
14ad2ba6d14b8d
1551cad21e3b38
hex284dcd7130b9

44314624340153 has 4 divisors (see below), whose sum is σ = 44314815903888. Its totient is φ = 44314432776420.

The previous prime is 44314624340143. The next prime is 44314624340167. The reversal of 44314624340153 is 35104342641344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44314624340153 - 210 = 44314624339129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44314624340143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95434451 + ... + 95897672.

It is an arithmetic number, because the mean of its divisors is an integer number (11078703975972).

Almost surely, 244314624340153 is an apocalyptic number.

It is an amenable number.

44314624340153 is a deficient number, since it is larger than the sum of its proper divisors (191563735).

44314624340153 is a wasteful number, since it uses less digits than its factorization.

44314624340153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191563734.

The product of its (nonzero) digits is 1658880, while the sum is 44.

Adding to 44314624340153 its reverse (35104342641344), we get a palindrome (79418966981497).

The spelling of 44314624340153 in words is "forty-four trillion, three hundred fourteen billion, six hundred twenty-four million, three hundred forty thousand, one hundred fifty-three".

Divisors: 1 231611 191332123 44314624340153