Base | Representation |
---|---|
bin | 100000010000011110111… |
… | …0000011000110111010001 |
3 | 120200211111012221012002011 |
4 | 1000200331300120313101 |
5 | 1040114142220010101 |
6 | 13232410103422521 |
7 | 635206556101360 |
oct | 100407560306721 |
9 | 16624435835064 |
10 | 4433442344401 |
11 | 145a237695324 |
12 | 5b7292a54a41 |
13 | 2620c1a2c635 |
14 | 114818bbb7d7 |
15 | 7a4cd7eb751 |
hex | 4083dc18dd1 |
4433442344401 has 16 divisors (see below), whose sum is σ = 5094802969344. Its totient is φ = 3779098251264.
The previous prime is 4433442344399. The next prime is 4433442344411. The reversal of 4433442344401 is 1044432443344.
It is not a de Polignac number, because 4433442344401 - 21 = 4433442344399 is a prime.
It is a super-2 number, since 2×44334423444012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4433442344411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3356745 + ... + 4487161.
It is an arithmetic number, because the mean of its divisors is an integer number (318425185584).
Almost surely, 24433442344401 is an apocalyptic number.
It is an amenable number.
4433442344401 is a deficient number, since it is larger than the sum of its proper divisors (661360624943).
4433442344401 is a wasteful number, since it uses less digits than its factorization.
4433442344401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1133520.
The product of its (nonzero) digits is 884736, while the sum is 40.
Adding to 4433442344401 its reverse (1044432443344), we get a palindrome (5477874787745).
The spelling of 4433442344401 in words is "four trillion, four hundred thirty-three billion, four hundred forty-two million, three hundred forty-four thousand, four hundred one".
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