Base | Representation |
---|---|
bin | 100000010000100000111… |
… | …1111111111001000000001 |
3 | 120200211200011220102000122 |
4 | 1000201001333333020001 |
5 | 1040114313431322040 |
6 | 13232421125430025 |
7 | 635211412214102 |
oct | 100410177771001 |
9 | 16624604812018 |
10 | 4433513542145 |
11 | 145a2738a4236 |
12 | 5b72b286b315 |
13 | 2621036ca38c |
14 | 1148244323a9 |
15 | 7a4d4bb21b5 |
hex | 40841fff201 |
4433513542145 has 4 divisors (see below), whose sum is σ = 5320216250580. Its totient is φ = 3546810833712.
The previous prime is 4433513542109. The next prime is 4433513542153. The reversal of 4433513542145 is 5412453153344.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1287171935296 + 3146341606849 = 1134536^2 + 1773793^2 .
It is a cyclic number.
It is not a de Polignac number, because 4433513542145 - 212 = 4433513538049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4433513542096 and 4433513542105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443351354210 + ... + 443351354219.
It is an arithmetic number, because the mean of its divisors is an integer number (1330054062645).
Almost surely, 24433513542145 is an apocalyptic number.
It is an amenable number.
4433513542145 is a deficient number, since it is larger than the sum of its proper divisors (886702708435).
4433513542145 is an equidigital number, since it uses as much as digits as its factorization.
4433513542145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 886702708434.
The product of its digits is 1728000, while the sum is 44.
Adding to 4433513542145 its reverse (5412453153344), we get a palindrome (9845966695489).
The spelling of 4433513542145 in words is "four trillion, four hundred thirty-three billion, five hundred thirteen million, five hundred forty-two thousand, one hundred forty-five".
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