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4434314132011 = 30707144407273
BaseRepresentation
bin100000010000111000110…
…1101111111101000101011
3120200220201222100120212011
41000201301231333220223
51040122433404211021
613233032405100351
7635240303135251
oct100416155775053
916626658316764
104434314132011
11145a6447a8255
125b74969b76b7
132622005288aa
1411489c8b25d1
157a530103de1
hex40871b7fa2b

4434314132011 has 4 divisors (see below), whose sum is σ = 4434458569992. Its totient is φ = 4434169694032.

The previous prime is 4434314132009. The next prime is 4434314132029. The reversal of 4434314132011 is 1102314134344.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4434314132011 - 21 = 4434314132009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4434354132011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72172930 + ... + 72234343.

It is an arithmetic number, because the mean of its divisors is an integer number (1108614642498).

Almost surely, 24434314132011 is an apocalyptic number.

4434314132011 is a deficient number, since it is larger than the sum of its proper divisors (144437981).

4434314132011 is a wasteful number, since it uses less digits than its factorization.

4434314132011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144437980.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4434314132011 its reverse (1102314134344), we get a palindrome (5536628266355).

The spelling of 4434314132011 in words is "four trillion, four hundred thirty-four billion, three hundred fourteen million, one hundred thirty-two thousand, eleven".

Divisors: 1 30707 144407273 4434314132011