Base | Representation |
---|---|
bin | 100000010000111001011… |
… | …0011101110110011000011 |
3 | 120200220210020202100211101 |
4 | 1000201302303232303003 |
5 | 1040123003044204443 |
6 | 13233034300555231 |
7 | 635240614415044 |
oct | 100416263566303 |
9 | 16626706670741 |
10 | 4434332413123 |
11 | 145a654054108 |
12 | 5b74a0b52b17 |
13 | 262204259812 |
14 | 1148a10b08cb |
15 | 7a531a1584d |
hex | 40872ceecc3 |
4434332413123 has 16 divisors (see below), whose sum is σ = 4454977661440. Its totient is φ = 4413746072736.
The previous prime is 4434332413117. The next prime is 4434332413183. The reversal of 4434332413123 is 3213142334344.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4434332413123 is a prime.
It is a super-2 number, since 2×44343324131232 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4434332413183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 453079036 + ... + 453088822.
It is an arithmetic number, because the mean of its divisors is an integer number (278436103840).
Almost surely, 24434332413123 is an apocalyptic number.
4434332413123 is a deficient number, since it is larger than the sum of its proper divisors (20645248317).
4434332413123 is a wasteful number, since it uses less digits than its factorization.
4434332413123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12586.
The product of its digits is 248832, while the sum is 37.
Adding to 4434332413123 its reverse (3213142334344), we get a palindrome (7647474747467).
The spelling of 4434332413123 in words is "four trillion, four hundred thirty-four billion, three hundred thirty-two million, four hundred thirteen thousand, one hundred twenty-three".
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