4440310413041 has 4 divisors (see below), whose sum is σ = 4440314905572. Its totient is φ = 4440305920512.

The previous prime is 4440310413029. The next prime is 4440310413047. The reversal of 4440310413041 is 1403140130444.

4440310413041 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 2357440876816 + 2082869536225 = 1535396^2 + 1443215^2 .

It is a cyclic number.

It is not a de Polignac number, because 4440310413041 - 2⁴² = 42263901937 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4440310412995 and 4440310413013.

It is not an unprimeable number, because it can be changed into a prime (4440310413047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43976 + ... + 2980361.

It is an arithmetic number, because the mean of its divisors is an integer number (1110078726393).

Almost surely, 2^{4440310413041} is an apocalyptic number.

It is an amenable number.

4440310413041 is a deficient number, since it is larger than the sum of its proper divisors (4492531).

4440310413041 is a wasteful number, since it uses less digits than its factorization.

4440310413041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4492530.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 4440310413041 its reverse (1403140130444), we get a palindrome (5843450543485).

The spelling of 4440310413041 in words is "four trillion, four hundred forty billion, three hundred ten million, four hundred thirteen thousand, forty-one".