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4440334420113 = 31480111473371
BaseRepresentation
bin100000010011101100010…
…0011100100100010010001
3120201111021112120220120120
41000213120203210202101
51040222301102420423
613235510024500453
7635542424552514
oct100473043444221
916644245526516
104440334420113
111462154025869
125b869701a729
1326294c878c47
14114cb0282d7b
157a7838e7ee3
hex409d88e4891

4440334420113 has 4 divisors (see below), whose sum is σ = 5920445893488. Its totient is φ = 2960222946740.

The previous prime is 4440334420091. The next prime is 4440334420157. The reversal of 4440334420113 is 3110244330444.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4440334420113 - 212 = 4440334416017 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4440334420183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 740055736683 + ... + 740055736688.

It is an arithmetic number, because the mean of its divisors is an integer number (1480111473372).

Almost surely, 24440334420113 is an apocalyptic number.

It is an amenable number.

4440334420113 is a deficient number, since it is larger than the sum of its proper divisors (1480111473375).

4440334420113 is a wasteful number, since it uses less digits than its factorization.

4440334420113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1480111473374.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 4440334420113 its reverse (3110244330444), we get a palindrome (7550578750557).

The spelling of 4440334420113 in words is "four trillion, four hundred forty billion, three hundred thirty-four million, four hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 1480111473371 4440334420113