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444104134433 = 1512941086983
BaseRepresentation
bin1100111011001101010…
…10110100111100100001
31120110022101021112112022
412131212222310330201
524234011124300213
6540004004511225
744041212600221
oct6354652647441
91513271245468
10444104134433
1116138622a383
12720a16ab515
1332b56a728cb
14176cd870081
15b843875308
hex6766ab4f21

444104134433 has 4 divisors (see below), whose sum is σ = 447045221568. Its totient is φ = 441163047300.

The previous prime is 444104134427. The next prime is 444104134469. The reversal of 444104134433 is 334431401444.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 444104134433 - 210 = 444104133409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 444104134393 and 444104134402.

It is not an unprimeable number, because it can be changed into a prime (444104134493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1470543341 + ... + 1470543642.

It is an arithmetic number, because the mean of its divisors is an integer number (111761305392).

Almost surely, 2444104134433 is an apocalyptic number.

It is an amenable number.

444104134433 is a deficient number, since it is larger than the sum of its proper divisors (2941087135).

444104134433 is a wasteful number, since it uses less digits than its factorization.

444104134433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2941087134.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 444104134433 its reverse (334431401444), we get a palindrome (778535535877).

The spelling of 444104134433 in words is "four hundred forty-four billion, one hundred four million, one hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 151 2941086983 444104134433