4441341340113 has 4 divisors (see below), whose sum is σ = 5921788453488. Its totient is φ = 2960894226740.

The previous prime is 4441341340057. The next prime is 4441341340123. The reversal of 4441341340113 is 3110431431444.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4441341340113 - 2¹⁰ = 4441341339089 is a prime.

It is a super-3 number, since 3×4441341340113³ (a number of 39 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (4441341340123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 740223556683 + ... + 740223556688.

It is an arithmetic number, because the mean of its divisors is an integer number (1480447113372).

Almost surely, 2^{4441341340113} is an apocalyptic number.

It is an amenable number.

4441341340113 is a deficient number, since it is larger than the sum of its proper divisors (1480447113375).

4441341340113 is a wasteful number, since it uses less digits than its factorization.

4441341340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1480447113374.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 4441341340113 its reverse (3110431431444), we get a palindrome (7551772771557).

The spelling of 4441341340113 in words is "four trillion, four hundred forty-one billion, three hundred forty-one million, three hundred forty thousand, one hundred thirteen".