Base | Representation |
---|---|
bin | 10100001101000111110100… |
… | …11100010011010110101011 |
3 | 12211022121001201101110102012 |
4 | 22012203322130103112223 |
5 | 21310430342404330011 |
6 | 234255251041030135 |
7 | 12234026052534314 |
oct | 1206437234232653 |
9 | 184277051343365 |
10 | 44431343433131 |
11 | 13180255055286 |
12 | 4b9711302534b |
13 | 1ba3b1c4ca965 |
14 | ad86ba61160b |
15 | 520b64118a8b |
hex | 2868fa7135ab |
44431343433131 has 6 divisors (see below), whose sum is σ = 47198693543460. Its totient is φ = 41817734995616.
The previous prime is 44431343433109. The next prime is 44431343433193. The reversal of 44431343433131 is 13133434313444.
It is a de Polignac number, because none of the positive numbers 2k-44431343433131 is a prime.
It is a super-2 number, since 2×444313434331312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (44431343432131) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 76870836101 + ... + 76870836678.
It is an arithmetic number, because the mean of its divisors is an integer number (7866448923910).
Almost surely, 244431343433131 is an apocalyptic number.
44431343433131 is a deficient number, since it is larger than the sum of its proper divisors (2767350110329).
44431343433131 is a wasteful number, since it uses less digits than its factorization.
44431343433131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153741672813 (or 153741672796 counting only the distinct ones).
The product of its digits is 746496, while the sum is 41.
Adding to 44431343433131 its reverse (13133434313444), we get a palindrome (57564777746575).
The spelling of 44431343433131 in words is "forty-four trillion, four hundred thirty-one billion, three hundred forty-three million, four hundred thirty-three thousand, one hundred thirty-one".
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