Base | Representation |
---|---|
bin | 110010101000101101100101… |
… | …1101001111100101010001011 |
3 | 2011102000211112211211112002211 |
4 | 1211101123023221330222023 |
5 | 431334413414004113003 |
6 | 4215141553243205551 |
7 | 162550045032503002 |
oct | 14521331351745213 |
9 | 2142024484745084 |
10 | 445400115301003 |
11 | 119a11145591a05 |
12 | 41b556395168b7 |
13 | 1616b087387c45 |
14 | 7bdb6a2ac3c39 |
15 | 3675d2c13d96d |
hex | 19516cba7ca8b |
445400115301003 has 4 divisors (see below), whose sum is σ = 445410354663000. Its totient is φ = 445389875939008.
The previous prime is 445400115300991. The next prime is 445400115301061. The reversal of 445400115301003 is 300103511004544.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-445400115301003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (445400115301403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5119615750 + ... + 5119702747.
It is an arithmetic number, because the mean of its divisors is an integer number (111352588665750).
Almost surely, 2445400115301003 is an apocalyptic number.
445400115301003 is a deficient number, since it is larger than the sum of its proper divisors (10239361997).
445400115301003 is a wasteful number, since it uses less digits than its factorization.
445400115301003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10239361996.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 445400115301003 its reverse (300103511004544), we get a palindrome (745503626305547).
The spelling of 445400115301003 in words is "four hundred forty-five trillion, four hundred billion, one hundred fifteen million, three hundred one thousand, three".
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