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44553014113 = 64369289291
BaseRepresentation
bin101001011111100100…
…010000101101100001
311020222222100121200211
4221133210100231201
51212221032422423
632244541414121
73135031241266
oct513744205541
9136888317624
1044553014113
1117993018a23
12877486a341
13428042b35a
14222915726d
15125b59810d
hexa5f910b61

44553014113 has 4 divisors (see below), whose sum is σ = 44622304048. Its totient is φ = 44483724180.

The previous prime is 44553014057. The next prime is 44553014159. The reversal of 44553014113 is 31141035544.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44553014113 - 229 = 44016143201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44553014173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34644003 + ... + 34645288.

It is an arithmetic number, because the mean of its divisors is an integer number (11155576012).

Almost surely, 244553014113 is an apocalyptic number.

It is an amenable number.

44553014113 is a deficient number, since it is larger than the sum of its proper divisors (69289935).

44553014113 is an equidigital number, since it uses as much as digits as its factorization.

44553014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69289934.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 44553014113 its reverse (31141035544), we get a palindrome (75694049657).

The spelling of 44553014113 in words is "forty-four billion, five hundred fifty-three million, fourteen thousand, one hundred thirteen".

Divisors: 1 643 69289291 44553014113