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4500133141211 = 19323316752027
BaseRepresentation
bin100000101111100010011…
…0101100101101011011011
3120221012122000102200120122
41001133010311211223123
51042212233041004321
613323155502543455
7643060331365331
oct101370465455333
916835560380518
104500133141211
11148554a927024
126081a5597b8b
1326848c6c1996
14117b440ddb51
157c0d363c8ab
hex417c4d65adb

4500133141211 has 4 divisors (see below), whose sum is σ = 4523449893432. Its totient is φ = 4476816388992.

The previous prime is 4500133141181. The next prime is 4500133141253. The reversal of 4500133141211 is 1121413310054.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4500133141211 - 238 = 4225255234267 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4500133141291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11658375821 + ... + 11658376206.

It is an arithmetic number, because the mean of its divisors is an integer number (1130862473358).

Almost surely, 24500133141211 is an apocalyptic number.

4500133141211 is a deficient number, since it is larger than the sum of its proper divisors (23316752221).

4500133141211 is a wasteful number, since it uses less digits than its factorization.

4500133141211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23316752220.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 4500133141211 its reverse (1121413310054), we get a palindrome (5621546451265).

The spelling of 4500133141211 in words is "four trillion, five hundred billion, one hundred thirty-three million, one hundred forty-one thousand, two hundred eleven".

Divisors: 1 193 23316752027 4500133141211