Search a number
-
+
45001345 = 59000269
BaseRepresentation
bin1010101110101…
…0101010000001
310010200022020111
42223222222001
543010020340
64244311321
71054335154
oct253525201
9103608214
1045001345
11234471a4
12130a2541
13942811c
145d95c9b
153e3daea
hex2aeaa81

45001345 has 4 divisors (see below), whose sum is σ = 54001620. Its totient is φ = 36001072.

The previous prime is 45001343. The next prime is 45001357. The reversal of 45001345 is 54310054.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 29767936 + 15233409 = 5456^2 + 3903^2 .

It is a cyclic number.

It is not a de Polignac number, because 45001345 - 21 = 45001343 is a prime.

It is not an unprimeable number, because it can be changed into a prime (45001343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4500130 + ... + 4500139.

It is an arithmetic number, because the mean of its divisors is an integer number (13500405).

Almost surely, 245001345 is an apocalyptic number.

It is an amenable number.

45001345 is a deficient number, since it is larger than the sum of its proper divisors (9000275).

45001345 is an equidigital number, since it uses as much as digits as its factorization.

45001345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9000274.

The product of its (nonzero) digits is 1200, while the sum is 22.

The square root of 45001345 is about 6708.3041821313. The cubic root of 45001345 is about 355.6928741333.

Adding to 45001345 its reverse (54310054), we get a palindrome (99311399).

The spelling of 45001345 in words is "forty-five million, one thousand, three hundred forty-five".

Divisors: 1 5 9000269 45001345