Base | Representation |
---|---|
bin | 110011001010100011011110… |
… | …1011101001001110101100011 |
3 | 2012000111111010202120020100201 |
4 | 1212111012331131021311203 |
5 | 432442120104110211101 |
6 | 4233102420352330031 |
7 | 163540064264563561 |
oct | 14625067535116543 |
9 | 2160444122506321 |
10 | 450051326647651 |
11 | 120444772095853 |
12 | 42586b66843917 |
13 | 16417872818851 |
14 | 7d1c85983ca31 |
15 | 3706d03d38e01 |
hex | 19951bd749d63 |
450051326647651 has 4 divisors (see below), whose sum is σ = 450361066034272. Its totient is φ = 449741587261032.
The previous prime is 450051326647649. The next prime is 450051326647661. The reversal of 450051326647651 is 156746623150054.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 450051326647651 - 21 = 450051326647649 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 450051326647592 and 450051326647601.
It is not an unprimeable number, because it can be changed into a prime (450051326647631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154869691131 + ... + 154869694036.
It is an arithmetic number, because the mean of its divisors is an integer number (112590266508568).
Almost surely, 2450051326647651 is an apocalyptic number.
450051326647651 is a deficient number, since it is larger than the sum of its proper divisors (309739386621).
450051326647651 is a wasteful number, since it uses less digits than its factorization.
450051326647651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 309739386620.
The product of its (nonzero) digits is 18144000, while the sum is 55.
The spelling of 450051326647651 in words is "four hundred fifty trillion, fifty-one billion, three hundred twenty-six million, six hundred forty-seven thousand, six hundred fifty-one".
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