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45031011331 = 182324701597
BaseRepresentation
bin101001111100000011…
…101011010000000011
311022020021210101121111
4221330003223100003
51214210414330311
632404214504151
73152624165215
oct517403532003
9138207711544
1045031011331
1118108917349
128888965057
13432847b547
1422728225b5
151288516d21
hexa7c0eb403

45031011331 has 4 divisors (see below), whose sum is σ = 45055714752. Its totient is φ = 45006307912.

The previous prime is 45031011329. The next prime is 45031011341. The reversal of 45031011331 is 13311013054.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 45031011331 - 21 = 45031011329 is a prime.

It is a super-3 number, since 3×450310113313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (45031011341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12348976 + ... + 12352621.

It is an arithmetic number, because the mean of its divisors is an integer number (11263928688).

Almost surely, 245031011331 is an apocalyptic number.

45031011331 is a deficient number, since it is larger than the sum of its proper divisors (24703421).

45031011331 is a wasteful number, since it uses less digits than its factorization.

45031011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24703420.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 45031011331 its reverse (13311013054), we get a palindrome (58342024385).

The spelling of 45031011331 in words is "forty-five billion, thirty-one million, eleven thousand, three hundred thirty-one".

Divisors: 1 1823 24701597 45031011331