Base | Representation |
---|---|
bin | 100000110001011111001… |
… | …1101100000100111010011 |
3 | 120221121102212212201022001 |
4 | 1001202332131200213103 |
5 | 1042244322202224021 |
6 | 13325131230054431 |
7 | 643266163624060 |
oct | 101427635404723 |
9 | 16847385781261 |
10 | 4504321133011 |
11 | 14872a9941277 |
12 | 608b7404a417 |
13 | 2689a9254a3b |
14 | 1180203cbc67 |
15 | 7c27b149091 |
hex | 418be7609d3 |
4504321133011 has 4 divisors (see below), whose sum is σ = 5147795580592. Its totient is φ = 3860846685432.
The previous prime is 4504321132981. The next prime is 4504321133021. The reversal of 4504321133011 is 1103311234054.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4504321133011 - 211 = 4504321130963 is a prime.
It is a super-2 number, since 2×45043211330112 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4504321133021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321737223780 + ... + 321737223793.
It is an arithmetic number, because the mean of its divisors is an integer number (1286948895148).
Almost surely, 24504321133011 is an apocalyptic number.
4504321133011 is a deficient number, since it is larger than the sum of its proper divisors (643474447581).
4504321133011 is an equidigital number, since it uses as much as digits as its factorization.
4504321133011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 643474447580.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 4504321133011 its reverse (1103311234054), we get a palindrome (5607632367065).
The spelling of 4504321133011 in words is "four trillion, five hundred four billion, three hundred twenty-one million, one hundred thirty-three thousand, eleven".
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