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45102113 = 76443159
BaseRepresentation
bin1010110000001…
…1010000100001
310010212102110122
42230003100201
543021231423
64250410025
71055235020
oct254032041
9103772418
1045102113
1123505981
1213130915
139461c54
145dc08b7
153e5d8c8
hex2b03421

45102113 has 4 divisors (see below), whose sum is σ = 51545280. Its totient is φ = 38658948.

The previous prime is 45102097. The next prime is 45102193. The reversal of 45102113 is 31120154.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 45102113 - 24 = 45102097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 45102091 and 45102100.

It is not an unprimeable number, because it can be changed into a prime (45102193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3221573 + ... + 3221586.

It is an arithmetic number, because the mean of its divisors is an integer number (12886320).

Almost surely, 245102113 is an apocalyptic number.

It is an amenable number.

45102113 is a deficient number, since it is larger than the sum of its proper divisors (6443167).

45102113 is an equidigital number, since it uses as much as digits as its factorization.

45102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6443166.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 45102113 is about 6715.8106733290. The cubic root of 45102113 is about 355.9581679795.

Adding to 45102113 its reverse (31120154), we get a palindrome (76222267).

The spelling of 45102113 in words is "forty-five million, one hundred two thousand, one hundred thirteen".

Divisors: 1 7 6443159 45102113