45112013054403 has 4 divisors (see below), whose sum is σ = 60149350739208. Its totient is φ = 30074675369600.

The previous prime is 45112013054401. The next prime is 45112013054527. The reversal of 45112013054403 is 30445031021154.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 45112013054403 - 2¹ = 45112013054401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (45112013054401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7518668842398 + ... + 7518668842403.

It is an arithmetic number, because the mean of its divisors is an integer number (15037337684802).

Almost surely, 2^{45112013054403} is an apocalyptic number.

45112013054403 is a deficient number, since it is larger than the sum of its proper divisors (15037337684805).

45112013054403 is a wasteful number, since it uses less digits than its factorization.

45112013054403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15037337684804.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 45112013054403 its reverse (30445031021154), we get a palindrome (75557044075557).

The spelling of 45112013054403 in words is "forty-five trillion, one hundred twelve billion, thirteen million, fifty-four thousand, four hundred three".