45134343141033 has 4 divisors (see below), whose sum is σ = 60179124188048. Its totient is φ = 30089562094020.

The previous prime is 45134343141001. The next prime is 45134343141103. The reversal of 45134343141033 is 33014134343154.

45134343141033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 45134343141033 - 2⁵ = 45134343141001 is a prime.

It is a super-2 number, since 2×45134343141033² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 45134343140982 and 45134343141000.

It is not an unprimeable number, because it can be changed into a prime (45134343141533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7522390523503 + ... + 7522390523508.

It is an arithmetic number, because the mean of its divisors is an integer number (15044781047012).

Almost surely, 2^{45134343141033} is an apocalyptic number.

It is an amenable number.

45134343141033 is a deficient number, since it is larger than the sum of its proper divisors (15044781047015).

45134343141033 is a wasteful number, since it uses less digits than its factorization.

45134343141033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15044781047014.

The product of its (nonzero) digits is 311040, while the sum is 39.

Adding to 45134343141033 its reverse (33014134343154), we get a palindrome (78148477484187).

The spelling of 45134343141033 in words is "forty-five trillion, one hundred thirty-four billion, three hundred forty-three million, one hundred forty-one thousand, thirty-three".