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4534113 = 31511371
BaseRepresentation
bin10001010010111101100001
322112100122010
4101102331201
52130042423
6241103133
753352663
oct21227541
98470563
104534113
112617601
121627aa9
13c29a0c
14860533
155e8693
hex452f61

4534113 has 4 divisors (see below), whose sum is σ = 6045488. Its totient is φ = 3022740.

The previous prime is 4534111. The next prime is 4534129. The reversal of 4534113 is 3114354.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4534113 - 21 = 4534111 is a prime.

It is a D-number.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4534113.

It is not an unprimeable number, because it can be changed into a prime (4534111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 755683 + ... + 755688.

It is an arithmetic number, because the mean of its divisors is an integer number (1511372).

Almost surely, 24534113 is an apocalyptic number.

It is an amenable number.

4534113 is a deficient number, since it is larger than the sum of its proper divisors (1511375).

4534113 is a wasteful number, since it uses less digits than its factorization.

4534113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1511374.

The product of its digits is 720, while the sum is 21.

The square root of 4534113 is about 2129.3456741450. The cubic root of 4534113 is about 165.5124928580.

Adding to 4534113 its reverse (3114354), we get a palindrome (7648467).

It can be divided in two parts, 45341 and 13, that added together give a palindrome (45354).

The spelling of 4534113 in words is "four million, five hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 1511371 4534113