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45553514001 = 315184504667
BaseRepresentation
bin101010011011001100…
…110111011000010001
311100120200222021112020
4222123030313120101
51221243144422001
632532121522053
73201600323502
oct523314673021
9140520867466
1045553514001
1118356853336
1289b3943329
1343ac7b1c18
1422c1d94ba9
1512b9327736
hexa9b337611

45553514001 has 4 divisors (see below), whose sum is σ = 60738018672. Its totient is φ = 30369009332.

The previous prime is 45553513987. The next prime is 45553514033. The reversal of 45553514001 is 10041535554.

45553514001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 45553514001 - 25 = 45553513969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (45553514101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7592252331 + ... + 7592252336.

It is an arithmetic number, because the mean of its divisors is an integer number (15184504668).

Almost surely, 245553514001 is an apocalyptic number.

It is an amenable number.

45553514001 is a deficient number, since it is larger than the sum of its proper divisors (15184504671).

45553514001 is a wasteful number, since it uses less digits than its factorization.

45553514001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15184504670.

The product of its (nonzero) digits is 30000, while the sum is 33.

The spelling of 45553514001 in words is "forty-five billion, five hundred fifty-three million, five hundred fourteen thousand, one".

Divisors: 1 3 15184504667 45553514001