Base | Representation |
---|---|
bin | 10101001111100001001110… |
… | …11110100111110100000001 |
3 | 20010101200201020101202212020 |
4 | 22213300213132213310001 |
5 | 22110320131010300423 |
6 | 243203310320552053 |
7 | 12560611625113506 |
oct | 1247604736476401 |
9 | 203350636352766 |
10 | 46712726650113 |
11 | 1397a835439777 |
12 | 52a52a5782629 |
13 | 200acb6939694 |
14 | b76c9d9014ad |
15 | 56018a1b64e3 |
hex | 2a7c277a7d01 |
46712726650113 has 4 divisors (see below), whose sum is σ = 62283635533488. Its totient is φ = 31141817766740.
The previous prime is 46712726650111. The next prime is 46712726650169. The reversal of 46712726650113 is 31105662721764.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 46712726650113 - 21 = 46712726650111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (46712726650111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7785454441683 + ... + 7785454441688.
It is an arithmetic number, because the mean of its divisors is an integer number (15570908883372).
Almost surely, 246712726650113 is an apocalyptic number.
It is an amenable number.
46712726650113 is a deficient number, since it is larger than the sum of its proper divisors (15570908883375).
46712726650113 is a wasteful number, since it uses less digits than its factorization.
46712726650113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15570908883374.
The product of its (nonzero) digits is 2540160, while the sum is 51.
The spelling of 46712726650113 in words is "forty-six trillion, seven hundred twelve billion, seven hundred twenty-six million, six hundred fifty thousand, one hundred thirteen".
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