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4712605125313 = 19961236090633
BaseRepresentation
bin100010010010011110100…
…1001111000101011000001
3121200112001112221210220011
41010210331021320223001
51104202403403002223
614004535122544521
7664321514430121
oct104447511705301
917615045853804
104712605125313
1115576718104a8
12641401b08141
1328252089b8b7
1412413c780c81
15828bb9b480d
hex4493d278ac1

4712605125313 has 4 divisors (see below), whose sum is σ = 4712841235908. Its totient is φ = 4712369014720.

The previous prime is 4712605125311. The next prime is 4712605125331. The reversal of 4712605125313 is 3135215062174.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2276030857104 + 2436574268209 = 1508652^2 + 1560953^2 .

It is a cyclic number.

It is not a de Polignac number, because 4712605125313 - 21 = 4712605125311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4712605125311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118025356 + ... + 118065277.

It is an arithmetic number, because the mean of its divisors is an integer number (1178210308977).

Almost surely, 24712605125313 is an apocalyptic number.

It is an amenable number.

4712605125313 is a deficient number, since it is larger than the sum of its proper divisors (236110595).

4712605125313 is a wasteful number, since it uses less digits than its factorization.

4712605125313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236110594.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 4712605125313 in words is "four trillion, seven hundred twelve billion, six hundred five million, one hundred twenty-five thousand, three hundred thirteen".

Divisors: 1 19961 236090633 4712605125313