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47472307340433 = 315824102446811
BaseRepresentation
bin10101100101101000000100…
…00001000000010010010001
320020002022022201110211121020
422302310002001000102101
522210241241134343213
6244544251003150053
712666522013340523
oct1262640201002221
9206068281424536
1047472307340433
111414298a9908a8
1253a854b815329
1320648089c1061
14ba1959b09a13
15574ce4c96923
hex2b2d02040491

47472307340433 has 4 divisors (see below), whose sum is σ = 63296409787248. Its totient is φ = 31648204893620.

The previous prime is 47472307340407. The next prime is 47472307340443. The reversal of 47472307340433 is 33404370327474.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 47472307340433 - 28 = 47472307340177 is a prime.

It is a super-4 number, since 4×474723073404334 (a number of 56 digits) contains 4444 as substring.

It is not an unprimeable number, because it can be changed into a prime (47472307340443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7912051223403 + ... + 7912051223408.

It is an arithmetic number, because the mean of its divisors is an integer number (15824102446812).

Almost surely, 247472307340433 is an apocalyptic number.

It is an amenable number.

47472307340433 is a deficient number, since it is larger than the sum of its proper divisors (15824102446815).

47472307340433 is a wasteful number, since it uses less digits than its factorization.

47472307340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15824102446814.

The product of its (nonzero) digits is 14224896, while the sum is 51.

The spelling of 47472307340433 in words is "forty-seven trillion, four hundred seventy-two billion, three hundred seven million, three hundred forty thousand, four hundred thirty-three".

Divisors: 1 3 15824102446811 47472307340433