Base | Representation |
---|---|
bin | 10101110000010001001111… |
… | …01111101110000110000001 |
3 | 20021101021021100101001022020 |
4 | 22320020213233232012001 |
5 | 22232234222204020331 |
6 | 245424251331232053 |
7 | 13035116355423243 |
oct | 1270104757560601 |
9 | 207337240331266 |
10 | 47838012563841 |
11 | 14273a94a59a25 |
12 | 54473b1748629 |
13 | 209014a256486 |
14 | bb552d2da093 |
15 | 57e59a9b4c96 |
hex | 2b8227bee181 |
47838012563841 has 16 divisors (see below), whose sum is σ = 67152115507200. Its totient is φ = 30208511260368.
The previous prime is 47838012563777. The next prime is 47838012563909. The reversal of 47838012563841 is 14836521083874.
It is not a de Polignac number, because 47838012563841 - 26 = 47838012563777 is a prime.
It is a super-2 number, since 2×478380125638412 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (47838012563041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68683221 + ... + 69376226.
It is an arithmetic number, because the mean of its divisors is an integer number (4197007219200).
Almost surely, 247838012563841 is an apocalyptic number.
It is an amenable number.
47838012563841 is a deficient number, since it is larger than the sum of its proper divisors (19314102943359).
47838012563841 is a wasteful number, since it uses less digits than its factorization.
47838012563841 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138065548.
The product of its (nonzero) digits is 30965760, while the sum is 60.
The spelling of 47838012563841 in words is "forty-seven trillion, eight hundred thirty-eight billion, twelve million, five hundred sixty-three thousand, eight hundred forty-one".
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