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4793009343433 = 41116902666913
BaseRepresentation
bin100010110111111010110…
…0111101000101111001001
3121222012121001200021220121
41011233311213220233021
51112012040342442213
614105513400223241
71003166145132163
oct105576547505711
917865531607817
104793009343433
111588781903643
12654b0116ab21
13289c95690c1c
14127da909b933
1584a256cb88d
hex45bf59e8bc9

4793009343433 has 4 divisors (see below), whose sum is σ = 4909912010388. Its totient is φ = 4676106676480.

The previous prime is 4793009343431. The next prime is 4793009343487. The reversal of 4793009343433 is 3343439003974.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2112362839609 + 2680646503824 = 1453397^2 + 1637268^2 .

It is a cyclic number.

It is not a de Polignac number, because 4793009343433 - 21 = 4793009343431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4793009343431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58451333416 + ... + 58451333497.

It is an arithmetic number, because the mean of its divisors is an integer number (1227478002597).

Almost surely, 24793009343433 is an apocalyptic number.

It is an amenable number.

4793009343433 is a deficient number, since it is larger than the sum of its proper divisors (116902666955).

4793009343433 is a wasteful number, since it uses less digits than its factorization.

4793009343433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 116902666954.

The product of its (nonzero) digits is 8817984, while the sum is 52.

The spelling of 4793009343433 in words is "four trillion, seven hundred ninety-three billion, nine million, three hundred forty-three thousand, four hundred thirty-three".

Divisors: 1 41 116902666913 4793009343433