Base | Representation |
---|---|
bin | 100011000001000100001… |
… | …0101011101001000000001 |
3 | 122001002021220100110001011 |
4 | 1012002020111131020001 |
5 | 1112322302034302332 |
6 | 14122522354440521 |
7 | 1004462653651246 |
oct | 106021025351001 |
9 | 18032256313034 |
10 | 4812650697217 |
11 | 1596040942430 |
12 | 658882b93141 |
13 | 28baa597605c |
14 | 128d0d8a55cd |
15 | 852c4c01e47 |
hex | 4608855d201 |
4812650697217 has 4 divisors (see below), whose sum is σ = 5250164396976. Its totient is φ = 4375136997460.
The previous prime is 4812650697199. The next prime is 4812650697221. The reversal of 4812650697217 is 7127960562184.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4812650697217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4812650695217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218756849863 + ... + 218756849884.
It is an arithmetic number, because the mean of its divisors is an integer number (1312541099244).
Almost surely, 24812650697217 is an apocalyptic number.
It is an amenable number.
4812650697217 is a deficient number, since it is larger than the sum of its proper divisors (437513699759).
4812650697217 is a wasteful number, since it uses less digits than its factorization.
4812650697217 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437513699758.
The product of its (nonzero) digits is 10160640, while the sum is 58.
The spelling of 4812650697217 in words is "four trillion, eight hundred twelve billion, six hundred fifty million, six hundred ninety-seven thousand, two hundred seventeen".
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