Base | Representation |
---|---|
bin | 100011000011000010110… |
… | …1101010000111100100001 |
3 | 122001111021011010101100001 |
4 | 1012012011231100330201 |
5 | 1112410003300340213 |
6 | 14124504245500001 |
7 | 1005003211552264 |
oct | 106060555207441 |
9 | 18044234111301 |
10 | 4816901574433 |
11 | 15979223a93a3 |
12 | 65966a711601 |
13 | 28c302556510 |
14 | 1291d4282cdb |
15 | 85472ed11dd |
hex | 46185b50f21 |
4816901574433 has 16 divisors (see below), whose sum is σ = 5201370720000. Its totient is φ = 4434426267840.
The previous prime is 4816901574431. The next prime is 4816901574449. The reversal of 4816901574433 is 3344751096184.
It is a cyclic number.
It is not a de Polignac number, because 4816901574433 - 21 = 4816901574431 is a prime.
It is a super-2 number, since 2×48169015744332 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4816901574431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47642068 + ... + 47743066.
It is an arithmetic number, because the mean of its divisors is an integer number (325085670000).
Almost surely, 24816901574433 is an apocalyptic number.
It is an amenable number.
4816901574433 is a deficient number, since it is larger than the sum of its proper divisors (384469145567).
4816901574433 is a wasteful number, since it uses less digits than its factorization.
4816901574433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110832.
The product of its (nonzero) digits is 8709120, while the sum is 55.
The spelling of 4816901574433 in words is "four trillion, eight hundred sixteen billion, nine hundred one million, five hundred seventy-four thousand, four hundred thirty-three".
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