Base | Representation |
---|---|
bin | 100011001001110001011… |
… | …0001101101001110010011 |
3 | 122002212112221110212101221 |
4 | 1012103202301231032103 |
5 | 1113124100031444221 |
6 | 14135253545105511 |
7 | 1006024206515155 |
oct | 106234261551623 |
9 | 18085487425357 |
10 | 4831347921811 |
11 | 15a2a65a48a64 |
12 | 660420788297 |
13 | 290795483668 |
14 | 129ba4b46ad5 |
15 | 85a1b3d0541 |
hex | 464e2c6d393 |
4831347921811 has 4 divisors (see below), whose sum is σ = 5085629391400. Its totient is φ = 4577066452224.
The previous prime is 4831347921787. The next prime is 4831347921817. The reversal of 4831347921811 is 1181297431384.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4831347921811 - 27 = 4831347921683 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4831347921817) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127140734766 + ... + 127140734803.
It is an arithmetic number, because the mean of its divisors is an integer number (1271407347850).
Almost surely, 24831347921811 is an apocalyptic number.
4831347921811 is a deficient number, since it is larger than the sum of its proper divisors (254281469589).
4831347921811 is a wasteful number, since it uses less digits than its factorization.
4831347921811 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 254281469588.
The product of its digits is 1161216, while the sum is 52.
The spelling of 4831347921811 in words is "four trillion, eight hundred thirty-one billion, three hundred forty-seven million, nine hundred twenty-one thousand, eight hundred eleven".
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