Base | Representation |
---|---|
bin | 101100111111111100… |
… | …001000010100001001 |
3 | 11121201022122120211220 |
4 | 230333330020110021 |
5 | 1242423221230221 |
6 | 34110252512253 |
7 | 3330230563551 |
oct | 547774102411 |
9 | 147638576756 |
10 | 48317367561 |
11 | 19544992431 |
12 | 944547b689 |
13 | 4730294628 |
14 | 24a508a161 |
15 | 13cbcc20c6 |
hex | b3ff08509 |
48317367561 has 4 divisors (see below), whose sum is σ = 64423156752. Its totient is φ = 32211578372.
The previous prime is 48317367533. The next prime is 48317367583. The reversal of 48317367561 is 16576371384.
48317367561 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 48317367561 - 211 = 48317365513 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (48317367521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8052894591 + ... + 8052894596.
It is an arithmetic number, because the mean of its divisors is an integer number (16105789188).
Almost surely, 248317367561 is an apocalyptic number.
It is an amenable number.
48317367561 is a deficient number, since it is larger than the sum of its proper divisors (16105789191).
48317367561 is a wasteful number, since it uses less digits than its factorization.
48317367561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16105789190.
The product of its digits is 2540160, while the sum is 51.
The spelling of 48317367561 in words is "forty-eight billion, three hundred seventeen million, three hundred sixty-seven thousand, five hundred sixty-one".
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