Base | Representation |
---|---|
bin | 100011001011011011000… |
… | …1010010011010110010001 |
3 | 122010012201002201200202121 |
4 | 1012112312022103112101 |
5 | 1113203330424041001 |
6 | 14141041513414241 |
7 | 1006211121665014 |
oct | 106266612232621 |
9 | 18105632650677 |
10 | 4834894362001 |
11 | 15a4515904a70 |
12 | 66105040a381 |
13 | 290c0c12cc92 |
14 | 12a01db5337b |
15 | 85b779126a1 |
hex | 465b6293591 |
4834894362001 has 8 divisors (see below), whose sum is σ = 5274581490144. Its totient is φ = 4395232446720.
The previous prime is 4834894361911. The next prime is 4834894362079. The reversal of 4834894362001 is 1002634984384.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4834894362001 - 29 = 4834894361489 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 4834894362001.
It is not an unprimeable number, because it can be changed into a prime (4834894362101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5901136 + ... + 6670321.
It is an arithmetic number, because the mean of its divisors is an integer number (659322686268).
Almost surely, 24834894362001 is an apocalyptic number.
It is an amenable number.
4834894362001 is a deficient number, since it is larger than the sum of its proper divisors (439687128143).
4834894362001 is a wasteful number, since it uses less digits than its factorization.
4834894362001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12606431.
The product of its (nonzero) digits is 3981312, while the sum is 52.
The spelling of 4834894362001 in words is "four trillion, eight hundred thirty-four billion, eight hundred ninety-four million, three hundred sixty-two thousand, one".
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