Base | Representation |
---|---|
bin | 100011001011011101100… |
… | …1111110100001001010001 |
3 | 122010012221001021222002001 |
4 | 1012112323033310021101 |
5 | 1113204014300140022 |
6 | 14141054202354001 |
7 | 1006213206203566 |
oct | 106267317641121 |
9 | 18105831258061 |
10 | 4834979693137 |
11 | 15a4559a97570 |
12 | 661074abb901 |
13 | 290c23a08a89 |
14 | 12a02b20686d |
15 | 85b8016ab27 |
hex | 465bb3f4251 |
4834979693137 has 16 divisors (see below), whose sum is σ = 5304456207360. Its totient is φ = 4370512118400.
The previous prime is 4834979693099. The next prime is 4834979693147. The reversal of 4834979693137 is 7313969794384.
It is not a de Polignac number, because 4834979693137 - 227 = 4834845475409 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 4834979693137.
It is not an unprimeable number, because it can be changed into a prime (4834979693147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4315789 + ... + 5319397.
It is an arithmetic number, because the mean of its divisors is an integer number (331528512960).
Almost surely, 24834979693137 is an apocalyptic number.
It is an amenable number.
4834979693137 is a deficient number, since it is larger than the sum of its proper divisors (469476514223).
4834979693137 is a wasteful number, since it uses less digits than its factorization.
4834979693137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1006104.
The product of its digits is 740710656, while the sum is 73.
The spelling of 4834979693137 in words is "four trillion, eight hundred thirty-four billion, nine hundred seventy-nine million, six hundred ninety-three thousand, one hundred thirty-seven".
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