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48383575033 = 172846092649
BaseRepresentation
bin101101000011111000…
…101100001111111001
311121212221020021102111
4231003320230033321
51243042143400113
634121015532321
73331663413343
oct550370541771
9147787207374
1048383575033
11195792a3052
12946368a0a1
134740c05b51
1424adba2293
1513d29ee13d
hexb43e2c3f9

48383575033 has 4 divisors (see below), whose sum is σ = 51229667700. Its totient is φ = 45537482368.

The previous prime is 48383575001. The next prime is 48383575081. The reversal of 48383575033 is 33057538384.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 32093647609 + 16289927424 = 179147^2 + 127632^2 .

It is a cyclic number.

It is not a de Polignac number, because 48383575033 - 25 = 48383575001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (48383575433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1423046308 + ... + 1423046341.

It is an arithmetic number, because the mean of its divisors is an integer number (12807416925).

Almost surely, 248383575033 is an apocalyptic number.

It is an amenable number.

48383575033 is a deficient number, since it is larger than the sum of its proper divisors (2846092667).

48383575033 is a wasteful number, since it uses less digits than its factorization.

48383575033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2846092666.

The product of its (nonzero) digits is 3628800, while the sum is 49.

The spelling of 48383575033 in words is "forty-eight billion, three hundred eighty-three million, five hundred seventy-five thousand, thirty-three".

Divisors: 1 17 2846092649 48383575033