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4841203266241 = 21312271798811
BaseRepresentation
bin100011001110010111000…
…1100110111001011000001
3122010210222210001020101121
41012130232030313023001
51113304241014004431
614144003523232241
71006523346536566
oct106345614671301
918123883036347
104841203266241
1115a7163041111
12662311218681
132916a61c3704
1412a45b9b286d
1585de6717611
hex4672e3372c1

4841203266241 has 4 divisors (see below), whose sum is σ = 4843475067184. Its totient is φ = 4838931465300.

The previous prime is 4841203266239. The next prime is 4841203266311. The reversal of 4841203266241 is 1426623021484.

4841203266241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4841203266241 - 21 = 4841203266239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4841207266241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1135897275 + ... + 1135901536.

It is an arithmetic number, because the mean of its divisors is an integer number (1210868766796).

Almost surely, 24841203266241 is an apocalyptic number.

It is an amenable number.

4841203266241 is a deficient number, since it is larger than the sum of its proper divisors (2271800943).

4841203266241 is a wasteful number, since it uses less digits than its factorization.

4841203266241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2271800942.

The product of its (nonzero) digits is 442368, while the sum is 43.

The spelling of 4841203266241 in words is "four trillion, eight hundred forty-one billion, two hundred three million, two hundred sixty-six thousand, two hundred forty-one".

Divisors: 1 2131 2271798811 4841203266241