Base | Representation |
---|---|
bin | 1110000110000111111… |
… | …11000011011100111011 |
3 | 1201022010101211220210111 |
4 | 13003003333003130323 |
5 | 30413344023022413 |
6 | 1010255013125151 |
7 | 46664003450155 |
oct | 7030377033473 |
9 | 1638111756714 |
10 | 484324423483 |
11 | 17744556888a |
12 | 79a473297b7 |
13 | 36896664304 |
14 | 196273c1ad5 |
15 | c8e9872d3d |
hex | 70c3fc373b |
484324423483 has 4 divisors (see below), whose sum is σ = 484336541800. Its totient is φ = 484312305168.
The previous prime is 484324423459. The next prime is 484324423487. The reversal of 484324423483 is 384324423484.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 484324423483 - 213 = 484324415291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (484324423487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5999010 + ... + 6079207.
It is an arithmetic number, because the mean of its divisors is an integer number (121084135450).
Almost surely, 2484324423483 is an apocalyptic number.
484324423483 is a deficient number, since it is larger than the sum of its proper divisors (12118317).
484324423483 is a wasteful number, since it uses less digits than its factorization.
484324423483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12118316.
The product of its digits is 7077888, while the sum is 49.
Subtracting from 484324423483 its reverse (384324423484), we obtain a palindrome (99999999999).
The spelling of 484324423483 in words is "four hundred eighty-four billion, three hundred twenty-four million, four hundred twenty-three thousand, four hundred eighty-three".
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