Base | Representation |
---|---|
bin | 10110000011111010110111… |
… | …11001101000000100000001 |
3 | 20100202211001010211121101211 |
4 | 23001331123321220010001 |
5 | 22324320012021110111 |
6 | 251102353310330121 |
7 | 13134651154246546 |
oct | 1301753371500401 |
9 | 210684033747354 |
10 | 48513197441281 |
11 | 14504371245771 |
12 | 55362237b9941 |
13 | 210ba0c57ab31 |
14 | bda0a0a20bcd |
15 | 591e16218521 |
hex | 2c1f5be68101 |
48513197441281 has 16 divisors (see below), whose sum is σ = 50115349001664. Its totient is φ = 46926393315264.
The previous prime is 48513197441243. The next prime is 48513197441329. The reversal of 48513197441281 is 18214479131584.
It is a cyclic number.
It is not a de Polignac number, because 48513197441281 - 211 = 48513197439233 is a prime.
It is a super-2 number, since 2×485131974412812 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (48513197441881) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 111691930 + ... + 112125436.
It is an arithmetic number, because the mean of its divisors is an integer number (3132209312604).
Almost surely, 248513197441281 is an apocalyptic number.
It is an amenable number.
48513197441281 is a deficient number, since it is larger than the sum of its proper divisors (1602151560383).
48513197441281 is a wasteful number, since it uses less digits than its factorization.
48513197441281 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 451200.
The product of its digits is 7741440, while the sum is 58.
The spelling of 48513197441281 in words is "forty-eight trillion, five hundred thirteen billion, one hundred ninety-seven million, four hundred forty-one thousand, two hundred eighty-one".
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