Base | Representation |
---|---|
bin | 101101010011000011… |
… | …001111010101000011 |
3 | 11122112122222022200021 |
4 | 231103003033111003 |
5 | 1244102311422103 |
6 | 34202145034311 |
7 | 3341203110421 |
oct | 552303172503 |
9 | 148478868607 |
10 | 48637998403 |
11 | 196999780a5 |
12 | 9514925997 |
13 | 4781836a17 |
14 | 24d58b0111 |
15 | 13ea008bbd |
hex | b530cf543 |
48637998403 has 4 divisors (see below), whose sum is σ = 48641157288. Its totient is φ = 48634839520.
The previous prime is 48637998379. The next prime is 48637998419. The reversal of 48637998403 is 30489973684.
48637998403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 48637998403 - 25 = 48637998371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (48637993403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1556233 + ... + 1587178.
It is an arithmetic number, because the mean of its divisors is an integer number (12160289322).
Almost surely, 248637998403 is an apocalyptic number.
48637998403 is a deficient number, since it is larger than the sum of its proper divisors (3158885).
48637998403 is a wasteful number, since it uses less digits than its factorization.
48637998403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3158884.
The product of its (nonzero) digits is 31352832, while the sum is 61.
The spelling of 48637998403 in words is "forty-eight billion, six hundred thirty-seven million, nine hundred ninety-eight thousand, four hundred three".
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