Base | Representation |
---|---|
bin | 100011011101110010011… |
… | …0011111010101100000001 |
3 | 122020222111120002111101111 |
4 | 1012323210303322230001 |
5 | 1114330112410304031 |
6 | 14211123113203321 |
7 | 1012105325036224 |
oct | 106734463725401 |
9 | 18228446074344 |
10 | 4874331728641 |
11 | 160a213207261 |
12 | 668817a00541 |
13 | 29485576a99b |
14 | 12bcc17035bb |
15 | 86bd4d0d1b1 |
hex | 46ee4cfab01 |
4874331728641 has 8 divisors (see below), whose sum is σ = 4916385802944. Its totient is φ = 4832452516080.
The previous prime is 4874331728633. The next prime is 4874331728663. The reversal of 4874331728641 is 1468271334784.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4874331728641 - 23 = 4874331728633 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4874331728341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43659445 + ... + 43770946.
It is an arithmetic number, because the mean of its divisors is an integer number (614548225368).
Almost surely, 24874331728641 is an apocalyptic number.
It is an amenable number.
4874331728641 is a deficient number, since it is larger than the sum of its proper divisors (42054074303).
4874331728641 is a wasteful number, since it uses less digits than its factorization.
4874331728641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87430871.
The product of its digits is 21676032, while the sum is 58.
The spelling of 4874331728641 in words is "four trillion, eight hundred seventy-four billion, three hundred thirty-one million, seven hundred twenty-eight thousand, six hundred forty-one".
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