Base | Representation |
---|---|
bin | 100011100110001000011… |
… | …0000001100110101111011 |
3 | 122022200202020021002200001 |
4 | 1013030100300030311323 |
5 | 1120123311144233430 |
6 | 14223245034453431 |
7 | 1013311325565355 |
oct | 107142060146573 |
9 | 18280666232601 |
10 | 4892248821115 |
11 | 1616877a11aa7 |
12 | 670198294277 |
13 | 29644c760656 |
14 | 12cb0110c0d5 |
15 | 873d2c8b3ca |
hex | 47310c0cd7b |
4892248821115 has 16 divisors (see below), whose sum is σ = 5923291572000. Its totient is φ = 3878744550912.
The previous prime is 4892248821113. The next prime is 4892248821133. The reversal of 4892248821115 is 5111288422984.
It is a cyclic number.
It is not a de Polignac number, because 4892248821115 - 21 = 4892248821113 is a prime.
It is a super-2 number, since 2×48922488211152 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4892248821113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4819096 + ... + 5745274.
It is an arithmetic number, because the mean of its divisors is an integer number (370205723250).
Almost surely, 24892248821115 is an apocalyptic number.
4892248821115 is a deficient number, since it is larger than the sum of its proper divisors (1031042750885).
4892248821115 is a wasteful number, since it uses less digits than its factorization.
4892248821115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 935646.
The product of its digits is 2949120, while the sum is 55.
The spelling of 4892248821115 in words is "four trillion, eight hundred ninety-two billion, two hundred forty-eight million, eight hundred twenty-one thousand, one hundred fifteen".
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