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48986511307 = 332914715083
BaseRepresentation
bin101101100111110100…
…101101011111001011
311200102221202121111121
4231213310231133023
51300311021330212
634300514540111
73352634322136
oct554764553713
9150387677447
1048986511307
1119858676a98
1295b1597637
134808abc086
142529cb121d
15141a8ebd07
hexb67d2d7cb

48986511307 has 4 divisors (see below), whose sum is σ = 49001229720. Its totient is φ = 48971792896.

The previous prime is 48986511239. The next prime is 48986511323. The reversal of 48986511307 is 70311568984.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48986511307 is a prime.

It is a super-3 number, since 3×489865113073 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (48986511397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7354213 + ... + 7360870.

It is an arithmetic number, because the mean of its divisors is an integer number (12250307430).

Almost surely, 248986511307 is an apocalyptic number.

48986511307 is a deficient number, since it is larger than the sum of its proper divisors (14718413).

48986511307 is a wasteful number, since it uses less digits than its factorization.

48986511307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14718412.

The product of its (nonzero) digits is 1451520, while the sum is 52.

The spelling of 48986511307 in words is "forty-eight billion, nine hundred eighty-six million, five hundred eleven thousand, three hundred seven".

Divisors: 1 3329 14715083 48986511307