49003113 has 4 divisors (see below), whose sum is σ = 65337488. Its totient is φ = 32668740.

The previous prime is 49003103. The next prime is 49003121. The reversal of 49003113 is 31130094.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 49003113 - 2⁵ = 49003081 is a prime.

It is a super-4 number, since 4×49003113⁴ (a number of 32 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 49003113.

It is not an unprimeable number, because it can be changed into a prime (49003103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8167183 + ... + 8167188.

It is an arithmetic number, because the mean of its divisors is an integer number (16334372).

Almost surely, 2^49003113 is an apocalyptic number.

It is an amenable number.

49003113 is a deficient number, since it is larger than the sum of its proper divisors (16334375).

49003113 is a wasteful number, since it uses less digits than its factorization.

49003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16334374.

The product of its (nonzero) digits is 324, while the sum is 21.

The square root of 49003113 is about 7000.2223536113. Note that the first 3 decimals coincide. The cubic root of 49003113 is about 365.9383201026.

The spelling of 49003113 in words is "forty-nine million, three thousand, one hundred thirteen".